f(t+1)=5x^2-4

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Solution for f(t+1)=5x^2-4 equation:


Simplifying
f(t + 1) = 5x2 + -4

Reorder the terms:
f(1 + t) = 5x2 + -4
(1 * f + t * f) = 5x2 + -4
(1f + ft) = 5x2 + -4

Reorder the terms:
1f + ft = -4 + 5x2

Solving
1f + ft = -4 + 5x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
4 + 1f + ft + -5x2 = -4 + 5x2 + 4 + -5x2

Reorder the terms:
4 + 1f + ft + -5x2 = -4 + 4 + 5x2 + -5x2

Combine like terms: -4 + 4 = 0
4 + 1f + ft + -5x2 = 0 + 5x2 + -5x2
4 + 1f + ft + -5x2 = 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0
4 + 1f + ft + -5x2 = 0

The solution to this equation could not be determined.

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